The total number of hydrogen bonds of a DNA-double Helix strand whose one strand has the following sequence of bases is_______.
$5^{\prime}$ - G - G-C-A-A-A-T-C-G-G-C-T-A-3'

Question

The total number of hydrogen bonds of a DNA-double Helix strand whose one strand has the following sequence of bases is_______. $5^{\prime}$ - G - G-C-A-A-A-T-C-G-G-C-T-A-3'

Aicharya · Accepted Answer

Two nucleic acid chains are wound about each other and held together by H bonds between pair of bases.
Adenine from two hydrogen bonds with thymine and Guanine form three hydrogen bond with cytosine.
$5^{\prime} \mathrm{G}-\mathrm{G}-\mathrm{C}-\mathrm{A}-\mathrm{A}-\mathrm{A}-\mathrm{T}-\mathrm{C}-\mathrm{G}-\mathrm{G}-\mathrm{C}-\mathrm{T}-\mathrm{A}-3^{\prime}$
In given DNA strand total seven guanine and cytosine bases which form total 21 H -bonds and six adenine and thymine base which will form total 12 H-bonds with other DNA strand.
Total no. of H bonds $=7 \times 3+6 \times 2=33$

The total number of hydrogen bonds of a DNA-double Helix strand whose one strand has the following sequence…

Solution