The total number of $\alpha$ and $\beta$-particles emitted in the nuclear reaction ${ }_{92}…

The total number of $\alpha$ and $\beta$-particles emitted in the nuclear reaction ${ }_{92} \mathrm{U}^{238} \longrightarrow{ }_{82} \mathrm{~Pb}^{214}$ is

Solution

${ }_{92} \mathrm{U}^{238} \rightarrow_{82} \mathrm{U}^{214}+6_2 \mathrm{He}^{\mathrm{H}}(\alpha)+2_{-1} e^0(\beta)$

Asked in: JEE Advanced 2009 (Paper 2)

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