The total internal energy of two mole monoatomic ideal gas at temperature T = 300   K will be _____ J .…

The total internal energy of two mole monoatomic ideal gas at temperature T=300 K will be _____ J. (Given R=8.31 J mol-1·K)

Solution

The internal energy of an ideal gas is a state function and is given by, U=nCvT.

For monatomic gas, Cv=32R.

Therefore, U=2×32×8.31×300=7479 J

Asked in: JEE Main 2022 (28 Jun Shift 1)

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