The total current supplied to the circuit by the battery is
The total current supplied to the circuit by the battery is

-
$1 \mathrm{~A}$
-
$2 \mathrm{~A}$
-
$4 A$
-
$6 \mathrm{~A}$
Solution
The given circuit can be written as
$
\mathrm{I}=\frac{6 \mathrm{~V}}{1.5 \Omega}=4 \mathrm{~A}
$
Asked in: JEE Main 2004
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