The total cost of $x$ books is $(x^{2} + 11x + 24)$ rupees. If the cost of one book is $(x+3)$ rupees, the…

The total cost of $x$ books is $(x^{2} + 11x + 24)$ rupees. If the cost of one book is $(x+3)$ rupees, the number of books is
  1. $x + 8$
  2. $x + 3$
  3. $x + 11$
  4. $x - 8$

Solution

Books $= \dfrac{x^{2}+11x+24}{x+3} = \dfrac{(x+3)(x+8)}{x+3} = x+8$.

Asked in: IMO

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