The total charge on the system of capacitance $C_{1} = 1 μF, C_{2} = 2 μF, C_{3} = 4 μF$ and $C_{4} = 3 μF$ connected in parallel is
(Assume a battery of $20 V$ is connected to the combination)

Question

The total charge on the system of capacitance

C_{1} = 1 μF, C_{2} = 2 μF, C_{3} = 4 μF

and

C_{4} = 3 μF

connected in parallel is
(Assume a battery of

20 V

is connected to the combination)

Aicharya · Accepted Answer

As the given capacitors are in parallel combination, therefore, $C_{eq} = (1 + 2 + 3 + 4) μF = 10 μF$
Hence, charge flown through the switch $∴ Q = (20 V) \times (10 μF) = 200 μ C$

The total charge on the system of capacitance C 1 = 1 μF , C 2 = 2 μF , C 3 = 4 μF and C 4 =…

Solution

The total charge on the system of capacitance C 1 = 1 &#956;F , C 2 = 2 &#956;F , C 3 = 4 &#956;F and C 4 =…

Solution

The total charge on the system of capacitance C 1 = 1 μF , C 2 = 2 μF , C 3 = 4 μF and C 4 =…