The torque due to the force $(2 \hat{i}+\hat{j}+2 \hat{k})$ about the origin, acting on a particle whose…

The torque due to the force $(2 \hat{i}+\hat{j}+2 \hat{k})$ about the origin, acting on a particle whose position vector is $(\hat{i}+\hat{j}+\hat{k})$, would be
  1. $\hat{i}-\hat{k}$
  2. $\hat{i}+\hat{k}$
  3. $\hat{j}+\hat{k}$
  4. $\hat{i}-\hat{j}+\hat{k}$

Solution

$\begin{aligned} \tau & =\dot{r} \times \dot{F} \\ \tau & =\left|\begin{array}{lll}\hat{i} & \hat{j} & \hat{k} \\ 1 & 1 & 1 \\ 2 & 1 & 2\end{array}\right| \\ \tau & =\hat{i}(2-1)-\hat{j}[0]+\hat{k}(1-2) \\ & =\hat{i}-\hat{k}\end{aligned}$

Asked in: JEE Main 2025 (22 Jan Shift 2)

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