The time taken by a particle executing simple harmonic motion of period $T$ to move from the mean position to half the maximum displacement is

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Aicharya · Accepted Answer

$\begin{aligned} & x=A \sin \omega t 	herefore \frac{A}{2}=A \sin \omega t \ & \omega t=\sin ^{-1}\left(\frac{1}{2}ight) 	herefore \frac{2 \pi}{T} t=\frac{\pi}{6} 	herefore t=\frac{T}{12} s\end{aligned}$

The time taken by a particle executing simple harmonic motion of period $T$ to move from the mean position…

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