The time period of a simple pendulum is given by T = 2 π l g . The measured value of the length of the…

The time period of a simple pendulum is given by T=2πlg. The measured value of the length of the pendulum is 10 cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1s resolution. The percentage accuracy in the determination of g using this pendulum is x. The value of x to the nearest integer is:-
  1. 2%
  2. 3%
  3. 5%
  4. 4%

Solution

g=4π2lT2
Δgg=Δll+2ΔTT=0.110+212000.5
Δgg=1100+150
Δgg×100=3%

Asked in: JEE Main 2021 (18 Mar Shift 1)

Practice more Mathematical Methods questions on Aicharya