The threshold frequency for a metallic surface corresponds to an energy of $6.2 \mathrm{eV}$, and the…
The threshold frequency for a metallic surface corresponds to an energy of $6.2 \mathrm{eV}$, and the stopping potential for a radiation incident on this surface $5 \mathrm{~V}$. The incident radiation lies in
X-ray region
ultra-violet region
infra-red region
visible region
Solution
$\lambda=\frac{1242 \mathrm{e} V \mathrm{~nm}}{11.2} \approx 1100 Å$
Ultraviolet region