The three sides of a triangle are given by $\left(x^2+7 x y+2 y^2\right)(y-1)=0$. Then the centroid of that…

The three sides of a triangle are given by $\left(x^2+7 x y+2 y^2\right)(y-1)=0$. Then the centroid of that triangle is
  1. $\left(\frac{2}{3}, 0\right)$
  2. $\left(\frac{7}{3}, \frac{2}{3}\right)$
  3. $\left(\frac{-7}{3}, \frac{2}{3}\right)$
  4. $\left(\frac{1}{3}, \frac{4}{3}\right)$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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