The three charges q 2 , q and q 2 are placed at the corners A , D and C of a square of side a as shown in…

The three charges q2,q and q2 are placed at the corners A,D and C of a square of side a as shown in figure. The magnitude of electric field E at the corner B of the square, is 

  1. q4πϵ0a212+12
  2. q4πϵ0a21+12
  3. q4πϵ0a21-12
  4. q4πϵ0a212-12

Solution

EA=kq2a2=kq2a2EC=kq2a2=kq2a2  and  ED=kq2a2=kq2a2

As we can see from diagram, EC & EA are perpendicular.

Therefore, net electric field will be,

=kq2a2+kq2a22+kq2a22=kq2a2+kq2a2=q4πϵ0a212+12

Asked in: JEE Main 2022 (28 Jun Shift 1)

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