The terminal voltage of the battery, whose emf is 10 V and internal resistance $1 \Omega$, when connected through an external resistance of $4 \Omega$ as shown in the figure is:

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Aicharya · Accepted Answer

Current in circuit $i=\frac{10}{4+1}=2 \mathrm{~A}$ $\begin{aligned} 	ext { Terminal voltage } & =E-i R \ & =10-2 	imes 1=8 \mathrm{~V} \end{aligned}$ ^

The terminal voltage of the battery, whose emf is 10 V and internal resistance $1 \Omega$, when connected…

Solution