The term independent of x in the expansion of x + 1 x 2 / 3 - x 1 / 3 + 1 - x - 1 x - x 1 / 2 10 , where x…

The term independent of x in the expansion of x+1x2/3-x1/3+1-x-1x-x1/210, where x0,1 is equal to

Solution

x+1x2/3-x1/3+1-x-1x-x1/210

x1/3+1x2/3-x1/3+1x2/3-x1/3+1-x1/2+1x1/2-1x1/2x1/2-110

=x1/3+1-x1/2+1x1/210

=x1/3-1x1/210

Now the r+1th Term

Tr+1=Cr10x1/310-r·-1x1/2r

Tr+1=Cr10x1/310-r·x-r/2-1r

For independent term

10-r3-r2=0r=4

T5=C410-14

=10×9×8×74×3×2×1=210

Asked in: JEE Main 2021 (25 Jul Shift 1)

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