The temperature of $K$ at which $\Delta G=0$, for a given reaction with $\Delta H=-20.5 \mathrm{~kJ}…
The temperature of $K$ at which $\Delta G=0$, for a given reaction with $\Delta H=-20.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $\Delta S=-50.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ is
$-410$
$410$
$2.44$
$-2.44$
Solution
From Gibbs-Helmholtz reaction,
$$
\begin{aligned}
\Delta G & =\Delta H-T \Delta S \\
0 & =-20.5 \times 10^3-T \times(-50.0) \\
\therefore T & =\frac{-20.5 \times 10^3}{-50.0}=410 \mathrm{~K}
\end{aligned}
$$
^