The temperature of an ideal gas in three dimensions is 300   K . The corresponding de-Broglie…

The temperature of an ideal gas in three dimensions is 300 K. The corresponding de-Broglie wavelength of the electron approximately at 300 K is:

me=mass of electron =9×10-31 kgh=Planck constant =6.6×10-34 J skB=Boltzmann constant=1.38×10-23 J K-1

  1. 2.26 nm
  2. 3.25 nm
  3. 8.46 nm
  4. 6.26 nm

Solution

k=1.38×10-23 J K-1

Mass of electron =9×10-31 kg

λD=h2m×32×kT=h3mkT

λD=6.6×10-343×9×10-31×1.38×10-23×300=6.6×10-34105.72×10-27=62 Aο

Thus x=62 Aο

Asked in: JEE Main 2021 (01 Sep Shift 2)

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