The temperature at which the speed of sound in air becomes double of its value at $27^\circ\text{C}$ is
The temperature at which the speed of sound in air becomes double of its value at $27^\circ\text{C}$ is
- $327^\circ\text{C}$
- $127^\circ\text{C}$
- $927^\circ\text{C}$
- $-123^\circ\text{C}$
Solution
Speed of sound, $v \propto \sqrt{T}$
$\therefore \frac{v}{2v} = \frac{\sqrt{273 + 27}}{\sqrt{T}}$ or $T = 1200\text{ K} = 927^\circ\text{C}$
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