The temperature at which 4 moles of a gas occupy $5 \mathrm{dm}^3$ volume at 3.32 bar pressure is

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Aicharya · Accepted Answer

For $n$ mole of an ideal gas, $\begin{aligned} & p V=n R T \ \Rightarrow \quad & \quad T=\frac{p V}{n R}=\frac{3.32 \times 5}{4 \times 0.082} \ = & 50.60 \mathrm{~K} \simeq 50 \mathrm{~K} \ \therefore p= & \text { pressure }=3.32 \mathrm{bar} \simeq 3.32 \mathrm{~atm} \ V= & \text { volume }=5 \mathrm{dm}^3=5 \mathrm{~L} \ n= & 4 \text { mol } \ R= & 0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} \end{aligned}$

The temperature at which 4 moles of a gas occupy \(5 \mathrm{dm}^3\) volume at 3.32 bar pressure is

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