$(p \vee q) \vee(\sim p \wedge \sim q) \equiv \ell$
Solution
Let $\mathrm{p}$ : the switch $\mathrm{S}_{1}$ is closed
$\mathrm{q}$ : The switch $\mathrm{S}_{2}$ is closed
$l:$ The lamp
Given circuit can be expressed as $(p \vee q) \vee(\sim p \wedge \sim q)$