The surface energy of a liquid drop is ' $U$ '. It splits up into 512 equal droplets. The surface energy becomes

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Aicharya · Accepted Answer

$\begin{aligned} & \frac{4}{3} \pi R^3=512 	imes \frac{4}{3} \pi r^3 \ & 	herefore r=\frac{R}{8} \ & U=4 \pi R^2 T \ & U^{\prime}=512 	imes 4 \pi r^2 T \ & =512 	imes \frac{4 \pi R^2 T}{64}=8\left(4 \pi R^2 Tight)=8 U\end{aligned}$

The surface energy of a liquid drop is ' $U$ '. It splits up into 512 equal droplets. The surface energy…

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