The sum of three numbers is 6 . Thrice the third number when added to the first number given 7 . On adding…

The sum of three numbers is 6 . Thrice the third number when added to the first number given 7 . On adding three time first number to the sum of second and third number we get 12 . The product of these numbers is
  1. $20$
  2. $3$
  3. $\frac{20}{3}$
  4. $\frac{5}{3}$

Solution

Let the numbers be $x, y, z$ $\begin{aligned} & x+y+z=6 ..(1)\\ & x+3 z==7 ..(2)\\ & 3 x+y+z=12..(3) \\ & \text { Eq. (3)-(1), gives } \\ & 2 x=6 \Rightarrow x=3 \end{aligned}$ $2 \mathrm{x}=6 \Rightarrow \mathrm{x}=3$ From eq. (2), we get $3+3 z+7 \Rightarrow z=\frac{4}{3}$ From eq. (1), we get $\begin{aligned} & 3+y+\frac{4}{3}=6 \quad \Rightarrow \quad y=\frac{5}{3} \\ & \therefore x y z=(3)\left(\frac{5}{3}\right)\left(\frac{4}{3}\right)=\frac{20}{3} \end{aligned}$

Asked in: MHT CET 2021 (22 Sep Shift 1)

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