The sum of the series : $(2)^2+2(4)^2+3(6)^2+\ldots$ upto 10 terms is :

The sum of the series : $(2)^2+2(4)^2+3(6)^2+\ldots$ upto 10 terms is :
  1. 11300
  2. 11200
  3. 12100
  4. 12300

Solution

$2^2+2(4)^2+3(6)^2+\ldots \ldots$ upto 10 terms $=2^2\left[1^3+2^3+3^3+\ldots \ldots\right.$ upto 10 terms $]$ $=4 \cdot\left(\frac{10 \times 11}{2}\right)^2=12100$

Asked in: JEE Main 2013 (23 Apr Online)

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