The sum of the series : $(2)^2+2(4)^2+3(6)^2+\ldots$ upto 10 terms is :
The sum of the series :
$(2)^2+2(4)^2+3(6)^2+\ldots$ upto 10 terms is :
-
11300
-
11200
-
12100
-
12300
Solution
$2^2+2(4)^2+3(6)^2+\ldots \ldots$ upto 10 terms $=2^2\left[1^3+2^3+3^3+\ldots \ldots\right.$ upto 10 terms $]$
$=4 \cdot\left(\frac{10 \times 11}{2}\right)^2=12100$
Asked in: JEE Main 2013 (23 Apr Online)
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