The sum of the series $1+\frac{1}{4.2 !}+\frac{1}{16.4 !}+\frac{1}{64.6 !}+\ldots \ldots \ldots$ ad inf. is
The sum of the series $1+\frac{1}{4.2 !}+\frac{1}{16.4 !}+\frac{1}{64.6 !}+\ldots \ldots \ldots$ ad inf. is
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$\frac{\mathrm{e}-1}{\sqrt{\mathrm{e}}}$
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$\frac{\mathrm{e}+1}{\sqrt{\mathrm{e}}}$
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$\frac{\mathrm{e}-1}{2 \sqrt{\mathrm{e}}}$
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$\frac{e+1}{2 \sqrt{e}}$
Solution
$\frac{e^x+e^{-x}}{2}=1+\frac{x^2}{2 !}+\frac{x^4}{4 !}+\frac{x^6}{6 !}+\ldots \ldots$
putting $x=1 / 2$ we get
$\frac{e+1}{2 \sqrt{e}}$
Asked in: JEE Main 2005
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