The sum of the series 2 . 20 C 0 + 5 . 20 C 1 + 8 . 20 C 2 + 11 . 20 C 3 + . . . . . . . + 62 . 20 C 20 is…

The sum of the series 2.20C0+5.20C1+8.20C2+11.20C3+.......+62.20C20 is equal to
  1. 226
  2. 225
  3. 224
  4. 223

Solution

Let,

S= 2.20C0+5.20C1+8.20C3+.......+62.20C20              ...i
S=62.20C0+59.20C1+56.20C3+.......+2.20C20       ...ii (Writing in reverse order nCr=nCn-r )
Adding i and ii
2S=64(20C0+20C1+20C2+.....+20C20)
S=32.220=225

Asked in: JEE Main 2019 (08 Apr Shift 1)

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