The sum of the exterior angles of any convex polygon, taken one at each vertex, is:
The sum of the exterior angles of any convex polygon, taken one at each vertex, is:
- $180^{\circ}$
- $360^{\circ}$
- Depends on the number of sides
- $(n-2) \times 180^{\circ}$
Solution
For ANY convex polygon, the sum of the exterior angles (one at each vertex) is always $360^{\circ}$, independent of the number of sides.
Asked in: IMO
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