The sum of the common terms of the following three arithmetic progressions. 3 , 7 , 11 , 15 , … &#8230…

The sum of the common terms of the following three arithmetic progressions.

3,7,11,15,,399

2,5,8,11,.........359  and

2,7,12,17,,197, is equal to _____ .

Solution

We have,

S1: 2,5,8,11,...,359

Common difference is d1=3

S2: 3,7,11,15...,399

Common difference is d2=4

S3:2,7,12,17...,197

Common difference is d3=5

Now taking LCM of common difference we get,

LCMd1, d2, d3=60

So, common terms are 47,107,167,

Hence, the sum will be 47+107+167=321.

Asked in: JEE Main 2023 (01 Feb Shift 2)

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