The sum of oxidation state of the metals in Fe ( CO ) 5 , VO 2 + and WO 3 is

In the complex $\mathrm{Fe}(\mathrm{CO}{)}_5$, take the oxidation number of $\mathrm{Fe}$ be $\mathrm{x}$ . Carbonyl is a neutral ligand which doesn't have any charge. So the oxidation number of $\mathrm{Fe}$ would be

$\mathrm{x}-0\times 5 = 0= 0$

Hence, the oxidation number of iron in this complex is$0$.

let oxidation state of vanadium in ${\mathrm{VO}}^{2+} = \mathrm{x}$.

so, $$\begin{gathered} \mathrm{x} + (-2) = +2 \\ \Rightarrow \mathrm{x} = +2 + 2 = +4 \end{gathered}$$

Tungsten trioxide consists of one tungsten atom and three oxygen atoms. Tungsten is a $\mathrm{d}-$block metal from group  $6$and has an oxidation state $+6$in the compound.

Then, Sum of oxidation state of metals in the given compounds $=10$