The sum of number of angular nodes and radial nodes for 4 d orbital is
- 2
- 3
- 4
- 5
Solution
Angular node $=l$ $\therefore$ for 4 d $\mathrm{n}=4, l=2$ Angular node $=2$ Radial node $=4-2-1=1$ Sum of angular + radial node $=3$
Asked in: AP EAMCET 2024 (23 May Shift 1)