The sum of coordination number and oxidation number of metal M in the complex M e n 2 C 2 O 4 C l (Where en…

$\left[\mathrm{M}{\left(\mathrm{e}\mathrm{n}\right)}_2\left({\mathrm{C}}_2{\mathrm{O}}_4\right)\right]\mathrm{C}\mathrm{l}$
Oxidation state of M = +3

en and oxalate ion are bidentate ligands. So, Coordination number of M = 6
Sum of oxidation state + Coordination number = 3 + 6 = 9