The sum of all four interior angles of any quadrilateral is:

The sum of all four interior angles of any quadrilateral is:
  1. $180^{\circ}$
  2. $270^{\circ}$
  3. $360^{\circ}$
  4. $540^{\circ}$

Solution

Using $(n-2) \times 180^{\circ}$ with $n = 4$: $2 \times 180^{\circ} = 360^{\circ}$.

Asked in: IMO

Practice more UNDERSTANDING QUADRILATERALS questions on Aicharya