The sum of 162 t h power of the roots of the equation x 3 - 2 x 2 + 2 x - 1 = 0 is ______.

The sum of 162th power of the roots of the equation x3-2x2+2x-1=0 is ______.

Solution

x3-2x2+2x-1=0

x=1 satisfying the equation

 x-1 is factor of x3-2x2+2x-1

=x-1x2-x+1=0

x=1,1+i32,1-i32

x=1,-ω2,-ω

sum of 162th power of roots

=1162+-ω2162+-ω162

=1+ω324+ω162

=1+1+1=3

Asked in: JEE Main 2021 (26 Feb Shift 1)

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