The sum of 10 values is 12 and the sum of their squares is 16.9 , then their standard deviation $(S, D)$ is

Question

Aicharya · Accepted Answer

Given $\sum x=12, \sum x^2=16.9$ and $n=10$ $\begin{aligned} & \because 	ext { S.D. }=\sqrt{\frac{\sum x^2}{n}-\left(\frac{\sum x}{n}ight)^2}=\sqrt{\frac{16.9}{10}-\left(\frac{12}{10}ight)^2} \ & =\sqrt{\frac{169-144}{100}}=\frac{5}{10}=0.5 \end{aligned}$

The sum of 10 values is 12 and the sum of their squares is 16.9 , then their standard deviation $(S, D)$ is

Solution