The successive ionization energy values of an element are 7 . 1 , 14 . 3 , 34 . 5 , 46 . 8 and 162 . 2 e V…

The successive ionization energy values of an element are 7.1, 14.3, 34.5, 46.8 and 162.2 eV respectively. The element is likely to be:
  1. Na
  2. Si
  3. F
  4. Ca

Solution

The IE1, IE2, IE3, IE4 and IE5 of an element are 7.1, 14.3, 34.5, 46.8 and 162.2 eV respectively. Therefore, We can see that there is a regular very close increment of ionization energy till the fourth ionization energy. After the fourth ionization energy, there is a sudden high jump in energy. It confirms that after losing four electrons, that element will achieve the noble gas configuration or stable configuration.

Na111s2 2s2 2p6 3s1

Si141s2 2s2 2p6 3s2 3p2

F91s2 2s2 2p5

We can see the configuration of the elements and can identify that silicon has this tendency to lose the four electrons and gets the noble gas configuration.

the valency of the element is 4 and it is most likely to be silicon.

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Asked in: JEE-TOPICTESTS-CHEMISTRY

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