The structure of a peptide is given below. If the absolute values of the net charge of the peptide at pH = 2…

The structure of a peptide is given below.   If the absolute values of the net charge of the peptide at pH=2, pH=6, and pH=11 are z1,z2, and z3, respectively, then what is z1+z2+z3?

Solution

The structure of tripeptide will be as followed at PH=2 (in highly acidic medium)

hence z1=2 at pH=6 (in approximately neutral solution it will be

Hence z2=0 pH=11 (in highly basic medium) the structure will be

Hence z3 will be 3.

Therefore z1+z2+z3=2+0+3=5.

Asked in: JEE Advanced 2020 (Paper 2)

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