The straight line, $2 x-3 y+17=0$ is perpendicular to the line passing through the points $(7,17)$ and $(15, \beta)$, then $\beta$ equals

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Aicharya · Accepted Answer

Slope of $2 x-3 y+17=0$ is $\frac{2}{3}$ Slope of line joining points $(7,17)$ and $(15, \beta)$ is $\frac{\beta-17}{15-7}=\frac{\beta-17}{8}$
Since, lines are perpendicular $\begin{aligned} & \frac{2}{3} \times \cdot \frac{\beta-17}{8}=-1 \\ & \Rightarrow \beta-17=-12 \quad \Rightarrow \beta=5 \end{aligned}$

The straight line, $2 x-3 y+17=0$ is perpendicular to the line passing through the points $(7,17)$ and $(15,…

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