
The stopping potential as a function of frequency of incident radiation is plotted for two different…

- greater than that of B.
- smaller than that of B.
- same as that of B.
- that no comparison can be made from the graphs.
Solution

Threshold frequency $\left(v_0\right)$ of A is less than B . $\therefore \quad$ Work function $\left(h v_0\right)$ of A is smaller than that of B.
Asked in: MHT CET 2024 (15 May Shift 2)
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