The stepwise stability constants of a complex are given below. What is its overall reaction stability…

The stepwise stability constants of a complex are given below. What is its overall reaction stability constant \(\left(\beta_4\right)\) ? \(\begin{aligned} & M+L \rightleftharpoons M L ; K_1=1.0 \times 10^4 \\ & M L+L \rightleftharpoons M L_2 ; K_2=1.0 \times 10^3 \\ & M L_2+L \rightleftharpoons M L_3 ; K_3=1.0 \times 10^3 \\ & M L_3+L \rightleftharpoons M L_4 ; K_4=1.0 \times 10^2 \end{aligned}\) (Overall reaction : \(M+4 L \rightleftharpoons M L_4\) )
  1. \(1.0 \times 10^{12}\)
  2. \(12.1 \times 10^3\)
  3. \(1.0 \times 10^6\)
  4. \(1.0 \times 10^8\)

Solution

Given, \(\begin{gathered} M+L \rightleftharpoons M L ; K_1=1.0 \times 10^4 \\ M L+L \rightleftharpoons M L_2 ; K_2=1.0 \times 10^3 \\ M L_2+L \rightleftharpoons M L_3 ; K_3=1.0 \times 10^3 \\ M L_3+L \rightleftharpoons M L_4 ; K_4=1.0 \times 10^2 \end{gathered}\) Overall reaction, \(M+4 L \rightleftharpoons M L_4\) The overall stability constant, \(\begin{aligned} \beta_4 & =K_1 \times K_2 \times K_3 \times K_4 \\ \beta_4 & =1.0 \times 10^4 \times 1.0 \times 10^3 \times 1 \times 10^3 \times 1 \times 10^2 \\ & =1 \times 10^{12} \end{aligned}\)

Asked in: AP EAMCET 2019 (23 Apr Shift 1)

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