The steady state current in| the circuit shown below is :

The steady state current in| the circuit shown below is :
  1. 0.67 A
  2. 1.5 A
  3. 2 A
  4. 1 A

Solution

At steady state, capacitor will be completely charged and will not allow current to pass through it. The simplified circuit will be :
$i=\frac{V}{R} \Rightarrow i=\frac{10}{2+3}=2 \mathrm{~A}$

Asked in: NEET 2024 (Re-NEET)

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