The statement pattern $\sim(p \leftrightarrow \sim q)$ is

The statement pattern $\sim(p \leftrightarrow \sim q)$ is
  1. equivalent to $(\sim p) \leftrightarrow q$
  2. a tautology
  3. a fallacy
  4. equivalent to $(p \leftrightarrow q)$

Solution

Hence $\sim(p \leftrightarrow \sim q) \equiv p \leftrightarrow q$

Asked in: MHT CET 2022 (08 Aug Shift 2)

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