The statement pattern $\sim(\mathrm{p} \vee \mathrm{q}) \vee(\sim \mathrm{p} \wedge \mathrm{q})$ is…
The statement pattern $\sim(\mathrm{p} \vee \mathrm{q}) \vee(\sim \mathrm{p} \wedge \mathrm{q})$ is equivalent to
- $\sim \mathrm{p}$
- $\mathrm{p}$
- $\sim q$
- $\mathrm{q}$
Solution
$\sim(p \vee q) \vee(\sim p \wedge q)$
$=(\sim p \wedge \sim q) \vee(\sim p \wedge q)$
$\equiv \sim p \wedge(\sim q \vee q)$
$\equiv \sim p \wedge T \cong \sim p$
Asked in: MHT CET 2020 (13 Oct Shift 2)
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