The statement $[\mathrm{p} \wedge(\mathrm{q} \vee \mathrm{r})] \vee[\sim \mathrm{r} \wedge \sim \mathrm{q}…

The statement $[\mathrm{p} \wedge(\mathrm{q} \vee \mathrm{r})] \vee[\sim \mathrm{r} \wedge \sim \mathrm{q} \wedge \mathrm{p}]$ is equivalent to
  1. $\sim r$
  2. $p$
  3. $\sim q$
  4. $q$

Asked in: MHT CET 2023 (14 May Shift 2)

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