The state of hybridization of $\mathrm{C}_2, \mathrm{C}_3, \mathrm{C}_5$ and $\mathrm{C}_6$ of the…
The state of hybridization of $\mathrm{C}_2, \mathrm{C}_3, \mathrm{C}_5$ and $\mathrm{C}_6$ of the hydrocarbon -
is in the following sequence :
- $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^3$ and $\mathrm{sp}^2$
- $\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}^2$ and $\mathrm{sp}^3$
- $\mathrm{sp}^3, \mathrm{sp}^2, \mathrm{sp}^2$ and $\mathrm{sp}$
- $\mathrm{sp}, \mathrm{sp}^2, \mathrm{sp}^2$ and $\mathrm{sp}^3$
Solution
$\begin{aligned}
& \mathrm{C}_2 \text { having } \rightarrow 2-\sigma \text { bond } \rightarrow \mathrm{sp} \\
& \mathrm{C}_3 \text { having } \rightarrow 4-\sigma \text { bond } \rightarrow \mathrm{sp}^3 \\
& \mathrm{C}_5 \text { having } \rightarrow 3-\sigma \text { bond } \rightarrow \mathrm{sp}^2 \\
& \mathrm{C}_6 \text { having } \rightarrow 4-\sigma \text { bond } \rightarrow \mathrm{sp}^3
\end{aligned}$
Asked in: NEET 2009 (Mains)
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