The standard oxidation potential \(E^{\circ}\) for the half cell reaction are $ \begin{array}{ll}…

The standard oxidation potential \(E^{\circ}\) for the half cell reaction are $ \begin{array}{ll} \mathrm{Zn} \rightarrow \mathrm{Zn}^{2+}+2 e^{-} ; & E^{\circ}=+0.76 \mathrm{~V} \\ \mathrm{Fe} \rightarrow \mathrm{Fe}^{2+}+2 e^{-} ; & E^{\circ}=+0.41 \mathrm{~V} \end{array} $ \(E M F\) of the cell reaction is $ \mathrm{Zn}+\mathrm{Fe}^{2+} \rightarrow \mathrm{Zn}^{2+}+\mathrm{Fe} $
  1. \(-0.35 \mathrm{~V}\)
  2. \(+0.35 \mathrm{~V}\)
  3. \(0.17 \mathrm{~V}\)
  4. \(1.17 \mathrm{~V}\).

Solution

$E_{\text {cell }}^{\circ}=0.76-0.41=0.35 \mathrm{~V}$

Asked in: MHT CET Full Test 5

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