The standard deviation of first 10 multiples of 4 is
The standard deviation of first 10 multiples of 4 is
- $7$
- $8$
- $11.5$
- $14$
Solution
Entries are $4,8,12,16,20,24,28,32,36,40$.
$
\begin{aligned}
\text { Variance } & =\frac{\sum_{i=1}^{10}(4 i)^2}{10}-\left(\frac{\sum_{i=1}^{10} 4 i}{10}\right)^2 \\
& =\frac{16 \times 10 \times 11 \times 21}{60}-\left(\frac{4 \times 55}{10}\right)^2 \\
& =132
\end{aligned}
$
$\therefore$ Standard deviation $=\sqrt{132} \approx 11.5$
Asked in: AP EAMCET 2022 (07 Jul Shift 2)
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