
The stability order of the following resonance structures is

- III < II < I
- II > I > III
- II < I < III
- II > III > I
Solution

Since, more electronegative atom consist negative charge. Hence, (II) is more stable as compared to (III). $\therefore$ Stability order $\rightarrow$ III $ < $ II $ < $ I Hence, option (a) is correct.
Asked in: AP EAMCET 2019 (20 Apr Shift 2)
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