The specific heat capacity of a monatomic gas at constant volume is $\mathrm{x} \%$ of its specific heat…
The specific heat capacity of a monatomic gas at constant volume is $\mathrm{x} \%$ of its specific heat capacity at constant pressure. Then $x=$
- $40$
- $50$
- $60$
- $75$
Solution
Specific heat capacity at constant volume $=\mathrm{x} \% \mathrm{x}$ specific heat capacity at constant pressure
$\begin{aligned}
& C_V=x \% \times C_P \\
& \frac{3}{2} R=x \% \times \frac{5}{2} R \Rightarrow x=60
\end{aligned}$
Asked in: AP EAMCET 2023 (15 May Shift 2)
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