The species, which has the bond order same as that of $\mathrm{F}_2$ molecule is
The species, which has the bond order same as that of $\mathrm{F}_2$ molecule is
$\mathrm{O}_2^{+}$
$\mathrm{O}_2^{2-}$
$\mathrm{O}_2$
$\mathrm{N}_2^{+}$
Solution
MO for the fluorine molecule, the 14 valence electrons of the fluorine atoms fill 4 bonding and 3 anti-bonding orbital thus bond order is 1 .
Bond order
$
=\frac{\text { bonding electrons }- \text { anti }- \text { bonding electrons }}{2}
$
In the same way $\mathrm{O}_2^{2-}$ has $2 \times(6)+2=14 e^{-}$ So, bond order is 1