The species that can have a trans-isomer is: ( e n   =   e t h a n e - 1 ,   2 - d i a m i n…

1. ${\left[\mathrm{C}\mathrm{r}{\left(\mathrm{e}\mathrm{n}\right)}_2\left(\mathrm{o}\mathrm{x}\right)\right]}^{+}$
2. $\left[\mathrm{P}\mathrm{t}\left(\mathrm{e}\mathrm{n}\right)\mathrm{C}{\mathrm{l}}_2\right]$
3. $\left[\mathrm{Z}\mathrm{n}\left(\mathrm{e}\mathrm{n}\right)\mathrm{C}{\mathrm{l}}_2\right]$
4. ${\left[\mathrm{P}\mathrm{t}{\left(\mathrm{e}\mathrm{n}\right)}_2\mathrm{C}{\mathrm{l}}_2\right]}^{2+}$

Solution

${\left[\mathrm{P}\mathrm{t}{\left(\mathrm{e}\mathrm{n}\right)}_2\left(\mathrm{C}{\mathrm{l}}_2\right)\right]}^{2+}$ Dichlorido-bis (ethane – 1, 2 – diamine) Platinum (IV) ion
Show geometrical isomers

Asked in: JEE Main 2019 (10 Apr Shift 1)

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