The spatial distribution of electric field due to charges $(\mathrm{A}, \mathrm{B})$ is shown in figure.…

The spatial distribution of electric field due to charges $(\mathrm{A}, \mathrm{B})$ is shown in figure. Which one of the following statements is correct?
  1. $\mathrm{A}$ is $+\mathrm{ve}$ and $\mathrm{B}-\mathrm{ve},|\mathrm{A}|>|\mathrm{B}|$
  2. $\mathrm{A}$ is $-\mathrm{ve}$ and $\mathrm{B}+\mathrm{ve},|\mathrm{A}|=|\mathrm{B}|$
  3. Both are +ve but $A>B$
  4. Both are $-$ ve but $A>B$

Solution

The lines proceed from the positive and lines will reach $\mathrm{B}$, if $\mathrm{B}$ is negative.
Greater intensity of lines near the charge signifies greater magnitude of charge.
So, $\mathrm{A}$ is positive, $\mathrm{B}$ is negative and $|\mathrm{A}|$ > $|\mathrm{B}|$.

Asked in: JEE Mains - Electrostatics - Test 1

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