The solutions of the equation 1 + sin 2 x sin 2 x sin 2 x cos 2 x 1 + cos 2 x cos 2 x 4 sin 2 x 4 sin 2 x 1…

The solutions of the equation 1+sin2xsin2xsin2xcos2x1+cos2xcos2x4sin2x4sin2x1+4sin2x=0,0<x<π, are
  1. π12,π6
  2. π6,5π6
  3. 5π12,7π12
  4. 7π12,11π12

Solution

1+sin2xsin2xsin2xcos2x1+cos2xcos2x4sin2x4sin2x1+4sin2x=0

use R1R1+R2+R3

2+4sin2x111cos2x1+cos2xcos2x4sin2x4sin2x1+4sin2x=0

use C1C1-C3  & C2C2-C3 

2+4sin2x00101cos2x-1-11+4sin2x=0

2+4sin2x=0

sin2x=-12

2x=π+π6,2π-π6

x=π2+π12,π-π12

Asked in: JEE Main 2021 (18 Mar Shift 1)

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